5r^2+56r+60=0

Solution for 5r^2+56r+60=0 equation:

5r^2+56r+60=0

a = 5; b = 56; c = +60;
Δ = b2-4ac
Δ = 562-4·5·60
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-44}{2*5}=\frac{-100}{10}
=-10
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+44}{2*5}=\frac{-12}{10}
=-1+1/5
$